The sum of three consecutive integers is 267. What is the largest integer? Numerical Answers Expected!
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Answered by
3
Let,
the 1st no. be x
the 2nd no. be x+1
the 3rd no. be x+2
A/Q,
x+x+1+x+2=267
3x+3=267
3x=264
x=88
Therefore,
the no. are
88,89,90
the 1st no. be x
the 2nd no. be x+1
the 3rd no. be x+2
A/Q,
x+x+1+x+2=267
3x+3=267
3x=264
x=88
Therefore,
the no. are
88,89,90
Answered by
3
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