Question

The sum of three consecutive integers is 36. Find the three integers.

Answer 1

Answer: x + (x + 2) + (x + 4) would equal 36

x + (x + 2) + (x + 4) = 36

3x + 6 = 36

3x = 30

x =10 ,x+2=12,x+4=14

So the three consecutive even integers are 10, 12, and 14.

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Answer 2

Answer:

Let

First consecutive = x

Second consecutive = x+1

Third consecutive = x+2

ATQ,

x + x+1 + x+2 = 36

3x + 3 =36

3x = 36 -- 3

x= 33/3

x = 11

First consecutive = 11

Second consecutive = 11+1 =12

Third consecutive =11+2= 13

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