Question

The sum of three consecutive integers is 36 the largest integer answer

Answer 1

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Let the three consecutive integers be x , x+1 and x+2 .

According to question,

$(x) + (x + 1) + (x + 2) = 36 \\ \\ x + x + 1 + x + 2 = 36 \\ \\ x + x + x + 1 + 2 = 36 \\ \\ 3x + 3 = 36 \\ \\ 3x = 36 - 3 \\ \\ 3x = 33 \\ \\ x = \frac{33}{11 } \\ \\ x = 11$

THE THREE CONSECUTIVE INTEGERS ARE
11 , 11+1 =12 and 11+2 =13

HENCE , THE LARGEST INTEGER IS 13 .

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#AADI 93