The sum of three consecutive integers is 39. Write an equation to model the situation
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Answered by
2
Answer:
let the numbers be x, x + 1 , x + 2
then
x+x+1+x+2 = 39
3x + 3 = 39
x+1= 13
x = 12
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Answered by
1
ANSWER
Let x,x+1,x+2 be the three consecutive numbers.
Let x,x+1,x+2 be the three consecutive numbers.Sum=x+x+1+x+2=39
Let x,x+1,x+2 be the three consecutive numbers.Sum=x+x+1+x+2=39⇒3x+3=39
Let x,x+1,x+2 be the three consecutive numbers.Sum=x+x+1+x+2=39⇒3x+3=39⇒3x=39−3=36
Let x,x+1,x+2 be the three consecutive numbers.Sum=x+x+1+x+2=39⇒3x+3=39⇒3x=39−3=36⇒x=
Let x,x+1,x+2 be the three consecutive numbers.Sum=x+x+1+x+2=39⇒3x+3=39⇒3x=39−3=36⇒x= 3
Let x,x+1,x+2 be the three consecutive numbers.Sum=x+x+1+x+2=39⇒3x+3=39⇒3x=39−3=36⇒x= 336
=12 on simplifying.
The numbers are 12 , 12+1, 12+2
Hence the three consecutive numbers are 12,13,14
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