Question

The sum of three consecutive integers is 48. Find the numbers.

Answer 1

The three consecutive integers are 15 , 16 , 17

Given :

The sum of three consecutive integers is 48

To find :

Find the numbers

Solution :

Step 1 of 2 :

Form the equation

Let three consecutive integers are x - 1 , x , x + 1

It is given that sum of three consecutive integers is 48

By the given condition

$\displaystyle \sf{(x - 1) + x + (x + 1 ) = 48}$

Step 2 of 2 :

Find the numbers

$\displaystyle \sf{(x - 1) + x + (x + 1 ) = 48}$

$\displaystyle \sf{ \implies 3x = 48}$

$\displaystyle \sf{ \implies x = \frac{48}{3} }$

$\displaystyle \sf{ \implies x = 16}$

First number = x - 1 = 16 - 1 = 15

Second number = x = 16

Third number = x + 1 = 16 + 1 = 17

Hence three consecutive integers are 15 , 16 , 17

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