the sum of three consecutive integers is same as their products .find the number
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SO, LET THE NUMBERS ARE X , X+1 , X+2
SUM OF NUMBERS = PRODUCT OF NUMBERS
==> X+X+1+X+2 = (X)(X+1)(X+2)
==> 3X+3 = X²+X (X+2)
==> 3X+3 = X³+2X²+X²+2X
==> 0 = X³+3X²+2X-3X-3
==> 0 = X³+3X²-X-3
LET X = 1
SO, (1)³+3(1)²-(1)-3
==> 1+3-3-1
==> SO, 1 IS FACTOR OF X³+3X²-X-3
X = 1 ,
X+1 = 2
X+2 = 3
SO, THREE NUMBERS ARE = 1,2,3
SO, VERIFY=>
X+X+1+X+2 = (X)(X+1)(X+2)
===> 1+2+3 = 1×2×3
==> 6 = 6
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