The sum of three consecutive multiple of 11 is 363 find the multipliplies
Answers
Answered by
0
Let first multiple be x+11
Then the second multiple will be x+22
Then the third multiple will be x+33
Their sum=363
Therefore,
x+11+x+22+x+33=363
3x+66=363
x+66=363/3=121
x=121-66
x=55 Ans.
Then the second multiple will be x+22
Then the third multiple will be x+33
Their sum=363
Therefore,
x+11+x+22+x+33=363
3x+66=363
x+66=363/3=121
x=121-66
x=55 Ans.
Answered by
6
hi mate!!
your answer is ______
↪let the first multiple be x
therefore the multiples are x, x +11, x +22
therefore x + x +11+ x +22 = 363
3x +33 = 363
3x = 330
x = 110
x +11 = 110 + 11 = 121
x +22 = 110 + 22 = 132
your answer is ______
↪let the first multiple be x
therefore the multiples are x, x +11, x +22
therefore x + x +11+ x +22 = 363
3x +33 = 363
3x = 330
x = 110
x +11 = 110 + 11 = 121
x +22 = 110 + 22 = 132
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