Question

The sum of three consecutive multiple of 3 is 333. Find the multiples.

Answer 1

Answer:

First Multiple = 108

Second Multiple = 111

Third Multiple = 114

Step-by-step explanation:

Let first multiple be x.

So , second multiple is x + 3.

So , third multiple is x + (2 X 3)

So, third multiple is x + 6.

According to question,

Sum of three consecutive multiples of 3 = 333.

Therefore ,

x + (x + 3) + (x + 6) = 333

→ x + x + 3 + x + 6 = 333

→ 3x + 9 = 333

→ 3x = 333 - 9

→ 3x = 324

→ x = 324/3

→ x = 108

First Multiple = x

First Multiple = 108

Second Multiple = x + 3

Second Multiple = 108 + 3

Second Multiple = 111

Third Multiple = x + (2 X3)

Third Multiple = x + 6

Third Multiple = 108 + 6

Third Multiple = 114

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Answer 2

Question:-

The sum of three consecutive multiple of 3 is 333. Find the multiples.

To find:-

Multiple of the number.

Solution :-

Let,

The Multiples be x, x + 3, x + 6.

According To The Question,

x + x + 3 + x + 6 = 333.

⇒ 3x + 9 = 333.

⇒ 3x = 333 - 9.

⇒ 3x = 324.

⇒ x = 324/3.

⇒ x = 108.

Now,

First Multiple = x = 108.

Second Multiple = x + 3 = 114.

Third Multiple = x + 6 = 117.