Question

the sum of three consecutive multiple of 8 is 888 find these multiple.
​

Answer 1

$\;\qquad\;\;\large{\odot\;\;\underline{\underline{\bf{\red{Your\; Question↷ }}}}}$

The sum of three consecutive multiple of 8 is 888 find these multiple.

$\huge\fbox\red{αη}\fbox\green{s}\fbox\pink{ωε}\fbox\purple{я}$

Refer to the attachment for process..

Answer:

$\mathcal{\implies{1st\;multiple= 8x=8\times{36}=288.}}$

$\mathcal{\implies{2nd\;multiple= 8(x+1)=8\times{37}=296.}}$

$\mathcal{\implies{2nd\;multiple= 8(x+2)=8\times{38}=304.}}$

$\large{\boxed{\mathfrak{\overbrace{\underbrace{\fcolorbox{r}{red}{Hope It Helps. ♡★❥✌ }}}}}}$

$\large{\boxed{\mathfrak{\overbrace{\underbrace{\fcolorbox{r}{red}{Hope It Helps. ♡★❥✌ }}}}}}$

Answer 2

Answer:

Fistr nioj

Step-by-step explanation:

let frist consicutive no. = x

second consicutive no. = x+8

third consicutive no. = x+16

sum of all =888

x+x=++ this line is wrong

x+x+8+x+16=888

3x+24=888

3x=888-24

x =888-24/3

x =864/3

x =288

hence frist no. =288 ,second no. =288+8 = 296 ,third no. =288+16=304