The sum of three consecutive multiple of 8 is 888 the least number among them
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Answered by
0
let three no's be x, x+8,x+16
x+ x+8+x+16 = 888
3x+ 24 = 888
3x= 864
x= 288
x+ x+8+x+16 = 888
3x+ 24 = 888
3x= 864
x= 288
Answered by
7
Here is your answer
Let,
The three consecutive multiples of 8 be x, x + 8 and x + 16.
x + (x + 8) + (x + 16) = 888 (Given)
⇒ 3x + 24 = 888
⇒ 3x = 888 – 24
⇒ 3x = 864
⇒ x = 288
Number are:-
x=288
x + 8 = 288 + 8 = 296
x + 16 = 288 + 16 = 304
Hence,
The three consecutive multiples of 8 are 288, 296 and 304.
Hope it helps you
Let,
The three consecutive multiples of 8 be x, x + 8 and x + 16.
x + (x + 8) + (x + 16) = 888 (Given)
⇒ 3x + 24 = 888
⇒ 3x = 888 – 24
⇒ 3x = 864
⇒ x = 288
Number are:-
x=288
x + 8 = 288 + 8 = 296
x + 16 = 288 + 16 = 304
Hence,
The three consecutive multiples of 8 are 288, 296 and 304.
Hope it helps you
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