Question

The sum of three consecutive multiples 8 is 216

Answer 1

Step-by-step explanation:

Let multiples be 8x, 8(x+1),8(x+2)

Given,

8x+8(x+1)+8(x+2)=216

8(x+x+1+x+2)=216

3x+3=216/8

3x+3=27

3x=27-3

3x=24

x=24/3

x=8

Therefore the multiples are

8x=8(8)=64

8(x+1)=8(8+1)=8(9)=72

8(x+2)=8(8+2)=8(10)=80

Therefore the multiples of 8 are 64,72,80