Question

The sum of three consecutive multiples of 11 is 132

Answer 1

Heya..

Here's your answer.....

Acc. to question

11x + 11x + 11 + 11x + 22 = 132

33x + 33 = 132

33x = 132-33

33x = 99

x = 99/33

x = 3

So, 11x = 11(3) = 33

11x + 11 = 33 + 11 = 44

11x + 22 = 55

Hence, the consecutive terms are:

33,44,55

Thanks....!!!!

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Sorry baby 'wink'

Answer 2

Given - Sum of three consecutive multiples of 11 is 132

Find - The consecutive multiple of 11

Solution - The three consecutive multiples of 11 are 33, 44 and 55.

Let the three consecutive multiples of 11 be x, x+11 and x+22.

So, as per the question their sum is 132. Representing this as mathematical equation-

x + x + 11 + x + 22 = 132

3x + 33 = 132

3x = 132 - 33

3x = 99

x = 33

So, first multiple of 11 is 33.

Second multiple of 11 is: x + 11

Second multiple of 11: 33 + 11

Second multiple of 11: 44

Third multiple of 11 is: x + 22

Third multiple of 11 is: 33 + 22

Third multiple of 11 is: 55

Thus, the three consecutive multiples of 11 are 33, 44 and 55.