The sum of three consecutive multiples of 11 is 198. Find the multiples.
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The consecutive multiples of 11 is x, x+11,x+22
x+x+11+x+22=198
3x+33=198
3x=198-33
3x=165
x=165/3
x=55
The numbers are 55,x+11=66,x+22=77
x+x+11+x+22=198
3x+33=198
3x=198-33
3x=165
x=165/3
x=55
The numbers are 55,x+11=66,x+22=77
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