Question

The sum of three consecutive multiples of 11 is 363. Find these multiples.

Answer 1

x+x+11+x+22=363
3x+33=363
3x=330
x=110
x+11=121
x+22=132
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Answer 2

let one multiple be x
second be x + 11
third be x+22
the sum of three multiples is 363
therefore, acc. to the statement
x+ x+ 11+ x +22=363
or 3x+33=363
or3x=330
or x=330/3=110
therefore
one=x=110
second x+ 11 =110 +11 =121
third x+ 22= 110 +22= 132