Question

the sum of three consecutive multiples of 11 is 363 . find its multiples

Answer 1

METHOD 1:Three consecutive multiples are 110,121 and 132 which has the sum of 363.

Solution:

Let us take the first number as 11 (C – 1)

First consecutive number that is a multiple of 11 is 11C

Second consecutive number that is a multiple of 11 is 11(C + 1)

Therefore, the sum of 3 multiple of 11 numbers is 11C + 11(C – 1) + 11(C + 1) = 363

Now the sum of 3 numbers are 11C + 11(C – 1) + 11(C + 1) = 363

33C = 363;  C = 33,  

By substituting C = 33 in numbers 11C, 11(C – 1) and 11(C + 1) we get values 110, 121, 132.  

METHOD 2:

Acc. to question

(x+(x+11)+(x+12))= 363

33+3x=363

x=110

Answer 2

Answer: 110 , 121 and 132

Step-by-step explanation:

Let the number's be x , x+11 , x+22.

x + x + 11 + x + 22 = 363

3x + 33 = 363

3x = 363 - 33 = 330

x = 330/3 = 110

x + 11 = 110 + 11 = 121

x + 22 = 110 + 22 = 132

Hence, the number's are 110 ,121 and 132.