Math, asked by Harshyadav97523, 2 months ago

the sum of three consecutive multiples of 11 is 468 find this multiples​

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Answered by suryakipooja
0

Answer. Three consecutive multiples are 110,121 and 132 which has the sum of 363. 33C = 363; C = 33, By substituting C = 33 in numbers 11C, 11(C – 1) and 11(C + 1) we get values 110, 121, 132

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