The sum of three consecutive multiples of 2 is 18. Find the numbers.
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Answered by
6
Answer :
4 , 6 , 8
Solution :
We know that , the consecutive multiples of 2 differ by 2 .
Thus ,
Let the three consecutive multiples of 2 be x , (x + 2) and (x + 4) .
Now ,
According to the question , the sum of three consecutive multiples of 2 is 18 .
Thus ,
=> x + (x + 2) + (x + 4) = 18
=> 3x + 6 = 18
=> 3x = 18 - 6
=> 3x = 12
=> x = 12/3
=> x = 4
Thus ,
1st no. = x = 4
2nd no. = x + 2 = 4 + 2 = 6
3rd no. = x + 4 = 4 + 4 = 8
Hence ,
Required numbers are 4 , 6 , 8 .
Answered by
0
Step-by-step explanation:
The sum of three consecutive multiples of 2 is 18.
the numbers are 4,6,8.
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