The sum of three consecutive multiples of 3 is 72.Find the number
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19
let multiples be 3x,3x+3,3x+6 3x+3x+3+3x+6=72 9x+9=72 9x=63 x=7 therefore numbers are 21,24,27
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9
Let the unknown multiples be x, x+3, x+6 x+x+3+x+6=72 = 3x+9=72 =3x=72-9=63 3x=63 x=21 x+3=24 & x+6=27.. Hope this answer will help you..
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