Question

The sum of three consecutive multiples of 3 is 72 . Find the numbers

Answer 1

X+x+3+x+6=72

3x+9=72

3x=63

X=21

Therefore the multiples of 3 whose sum is 72 are21,24,and27

Answer 2

3x+3(x+1)+3(x+2)=72

3x+3x+3+3x+6=72

9x+9=72

9x=72-9=63

x=63/9=7

3*7=21

3(7+1)=24

3(7+2)=42

I HOPE IT HELPS U