The sum of three consecutive multiples of 4 is 252 find the numbers
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Answered by
0
Hi Friend !!!!
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let the multiples of 4 are 4x,4x+4 and 4x+8
4x + 4x + 4 + 4x + 8 = 252
12x + 12 = 252
12(x+1) = 252
x+1 = 252/12
x + 1 = 21
x = 21 - 1
x = 20
the multiples are 20 , 24 and 28
Hope it helps u
:-)
===================
let the multiples of 4 are 4x,4x+4 and 4x+8
4x + 4x + 4 + 4x + 8 = 252
12x + 12 = 252
12(x+1) = 252
x+1 = 252/12
x + 1 = 21
x = 21 - 1
x = 20
the multiples are 20 , 24 and 28
Hope it helps u
:-)
Answered by
8
HELLO......FRIEND!!
THE ANSWER IS HERE,
Let the consecutive numbers be 4x, 4x+4 & 4x+8.
From the question,
=> 4x+4x+4+4x+8=256
=> 12x+12=256
=> 12 (x+1)=256
=> x+1=256/12
=> x+1=21
=> x=20.
So, The numbers are 4(20) ; 4 (20)+4 & 4 (20)+8
=> 80 ; 84 & 88
:-)Hope it helps u.
THE ANSWER IS HERE,
Let the consecutive numbers be 4x, 4x+4 & 4x+8.
From the question,
=> 4x+4x+4+4x+8=256
=> 12x+12=256
=> 12 (x+1)=256
=> x+1=256/12
=> x+1=21
=> x=20.
So, The numbers are 4(20) ; 4 (20)+4 & 4 (20)+8
=> 80 ; 84 & 88
:-)Hope it helps u.
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