Question

the sum of three consecutive multiples of 4 is 252 find them

Answer 1

Let the  no be

• x-4
• x
• x+4
• A/Q,  x-4+x+x+4 = 252

    3 x = 252

      x = 84

so

No  =

• 80
• 84
• 88

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Answer 2

$\underline \bold{Solution:-}$

Let the three consecutive multiples of 4 are 4x , 4(x + 1) , and 4(x + 2).

According to question

$4x + 4(x + 1) + 4(x + 2) = 252 \\ \\ 4x + 4x + 4 + 4x + 8 = 252 \\ \\ 12x + 12 = 252 \\ \\ 12x = 252 - 12 \\ \\ 12x = 240 \\ \\ on \: dividing \: both \: sides \: by \: 12 \\ \\ x = \frac{240}{12} \\ \\ x = 20$

So, the numbers are

4x = 4×20 = 80

4(x + 1) = 4(20 + 1) = 4 × 21 =84

4(x + 1) = 4(20 + 2) = 4 × 22 =88