the sum of three consecutive multiples of 4 is 252. Ind multiplied
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Answered by
4
let the multiples be
4x ,4x+4,4x+8
there sum is 252
so
4x+4x+4+4x+8=252
12x+12=252
12x= 240
x=20
4x=80
4x+4=84
4x+8=88
4x ,4x+4,4x+8
there sum is 252
so
4x+4x+4+4x+8=252
12x+12=252
12x= 240
x=20
4x=80
4x+4=84
4x+8=88
AnanyaSrivastava999:
9th
Answered by
2
Let one of the multiples be x. Because they are consecutive integers and multiples of 4
the three would be:
x , x + 4, x + 8
Now, because their sum is 252, the equation would become:
x+x+4+x+8=252
3x+12=252
3x=252-12
3x=240
x=240/3
x=80
Now putting the value of x,
x =80
x+4=80+4=84
x+8=80+8=88
therefore the 3 multiples are 80,84,88
the three would be:
x , x + 4, x + 8
Now, because their sum is 252, the equation would become:
x+x+4+x+8=252
3x+12=252
3x=252-12
3x=240
x=240/3
x=80
Now putting the value of x,
x =80
x+4=80+4=84
x+8=80+8=88
therefore the 3 multiples are 80,84,88
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