Question

The sum of three consecutive multiples of 5 is 330. find the smallest integer ​

Answer 1

Answer:

don't know sorry...okokk

Answer 2

$\huge\bf\pink{\mid{\overline{\underline{Given :- }}}\mid}$

• The sum of three consecutive multiples of 5 is 330.

$\huge\bf\orange{\mid{\overline{\underline{To\:Find :- }}}\mid}$

• The smallest integer .

$\huge\bf\red{\mid{\overline{\underline{Answer :- }}}\mid}$

Let us suppose,

The consecutive multiples of 5 be,

• x
• ( x + 5 )
• ( x + 10 )

According to the question,

The sum of three consecutive multiples of 5 is 330.

x + (x + 5) + (x + 10) = 330

➝ x + x + x + 5 + 10 = 330

➝ 3x + 15 = 330

➝ 3x = 330 - 15

➝ 3x = 315

➝ x = $\cancel{\dfrac{315}{3}}$

➝ x = 105

The consecutive multiples of 5 are :-

• x = 105

• ( x + 5 ) = 105 + 5 = 110

• ( x + 10 ) = 105 + 10 = 115

The smallest integer among the three is 105.