Question

The sum of three consecutive multiples of 6 is 126.Find these three multiples.

Answer 1

let first multiple of 6 be x

second one is x+6

third one is 12+x

x+x+6+x+12=126

3x+18=126

3x=108

x=36

hence, three multiples are 36,42 and 48

Plz mark as brainleist!!

Answer 2

Answer:Let the 3 multiple of 6 be = x, x+6, x+12

126=x+x+6+x+12

126=3x+18

108=3x

X=37

Multiple are 37,43,46