Question

The sum of three consecutive multiples of 6 is 196. Find

the multiple​

Answer 1

Answer:

I think the question is The sum of three consecutive multiples of 6 is 126. Find

the multiple

Step-by-step explanation:

let the multiple of 6 be x

and second consecutive multiple be x+6

and 3rd consecutive multiple be x+12

so,

x+x+6+x+12= 126

3x+18=126

3x= 126-18

3x= 108

×=36

36 , 36+6 , 36+12

the three consecutive multiples of 6 are 36, 42, 48

36+42+48= 126

Answer 2

Correct Question:

The sum of three consecutive multiples of 6 is 126. Find the multiples.

[ We can't take 196 because it is not the multiple of 6. We can take 126. ].

Given:

✰ The sum of three consecutive multiples of 6 is 126.

To find:

✠ The multiplies of 6.

Solution:

Let's understand the concept first! First we will assume that the three consecutive multiples of 6 be 6x, 6(x + 1) and 6(x + 2) and then we know that their sum is equal to 126. Thus, forming an adequate equation and doing the required calculations we will find the value of x. After finding the value of x, we will substitute the value of x in these numbers and find out the three consecutive multiples of 6.

Let's find out...♪

Let the three consecutive multiples of 6 be 6x , 6(x + 1) and 6(x + 2)

➝ 6x, 6x + 6 and 6x + 12

According to question,

➛ 6x + 6x + 6 + 6x + 12 = 126

➛ 18x + 18 = 126

➛ 18x = 126 - 18

➛ 18x = 108

➛ x = 108/18

➛ x = 6

Now, let's find out the three consecutive multiples of 6.

⟹ First multiple = 6x

⟹ First multiple = 6 × 6

⟹ First multiple = 36

⟹ Second multiple = 6x + 6

⟹ Second multiple = 6 × 6 + 6

⟹ Second multiple = 36 + 6

⟹ Second multiple = 42

⟹ Third multiple = 6x + 12

⟹ Third multiple = 6 × 6 + 12

⟹ Third multiple = 36 + 12

⟹ Third multiple = 48

∴ The three consecutive multiples of 6 are 36, 42 and 48 respectively.

Verification:

L.H.S

⇾ 36 + 42 + 48

⇾ 126

R.H.S

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