Question

the sum of three consecutive multiples of 7 is 273 one of the three numbers is

a.77
b.98
c.105
d.112​

Answer 1

the sum of three consecutive multiples of 7 is 273 one of the three numbers is

a.77

b.98

c.105

d.112 Answer is c 105

Answer 2

One of the three numbers is (b) 98.

Given: The sum of three consecutive multiples of 7 is 273.

To Find: One of the three numbers.

Solution:

Since we need to find the consecutive multiples of 7, so we can take the integers as 7x, 7 (x+1), and 7 (x+2).

According to the problem, the sum of the integers is 273, so framing an equation, we get;

      7x + 7 × ( x + 1 ) + 7 × ( x + 2 ) = 273

  ⇒ 21x + 21 = 273

  ⇒  21x = 252

  ⇒  x = 252 / 21

  ⇒  x = 12

So, the numbers are 7×12 = 84,

7 × ( 12 + 1 ) = 91,

7 × ( x + 2 ) = 98.

From the given options, we see that one of the 3 numbers is 98.

Hence, one of the three numbers is (b) 98.

#SPJ2