Question

the sum of three consecutive multiples of 7 is 777. Find these multiples.

Answer 1

Let the first Number = 7x

2 Nd number = 7x+7

3rd Number = 7x+14

Now,

According to the Question :

7x+7x+7+7x+14 = 777

21x+21 = 777

21x = 777-21 = 756

x = 756/21 = 36 .

Now ,

First Number = 7x = 7(36) = 252

2 Nd Number = 7x+7 = 252+7 = 259

3 rd Number = 7x+14 = 252+14 = 266

★ AhseFurieux ★

Answer 2

Solutions :-


Let the first number be 7x
Second number = 7x + 7
Third number = 7x + 14


We know that,
The sum of three consecutive multiples of 7 is 777


A/q

=> 7x + 7x + 7 + 7x + 14 = 777
=> (7x + 7x + 7x) + (7 + 14) = 777
=> 21x + 21 = 777
=> 21x = 777 - 21
=> 21x = 756
=> x = 756/21 = 36


Therefore,
first number = 7x = 7 × 36 = 252
Second number = 7x + 7 = (7 × 36) + 7 = 259
Third number = 7x + 14 = (7 × 36) + 14 = 266


Hence,
The sum of 252, 259 and 266 is 777.