Math, asked by rohitsumit, 1 year ago

The sum of three consecutive multiples of 8 is 888.Find the multiples.

Answers

Answered by Anonymous
1658
Let the multiples be x+8, x+16 and x+24
According to Question:

x+8 + x+16 + x+24 = 888
3x + 48 = 888
3x = 888-48
3x = 840
x = 840/3
x = 280

x+8 = 280+8 → 288
x+16 = 280+16 → 296
x+24 = 280+24 → 304

Hope this helps •_•

Princy11: nice answer
Answered by Anonymous
331
hello there !
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Let the three consecutive multiples of 8 is 8n , 8n+ 8 , 8n + 16 

ATQ 

8n + 8n + 8 + 8n + 16 = 888 
24n + 24                     = 888 
24(n+1)                      =  888
n+ 1                           = 37 
n                                = 36 
8n                              = 288
8n+8                          = 296 
8n+16                        = 304 
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