Question

The sum of three consecutive multiples of 8 is 888. Find the multiples.
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Answer 1

Answer:

let 3 consecutive multiples of 8 be

8x, 8(x+1), 8(x+2)

-> By the given terms

8x + 8(x+1) + 8(x+2) = 888

8(x + x + 1 + x + 2)= 888

3x+3= 888

8

3x+3 = 111

3x=111-3

3x= 108

x= 108

3

x= 36

8x=36×8=288

8(x+1)= 8×36+1

=8+37

=296

8(x+2)=8×36+2

=8×36+2

=309

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Answer 2

Answer:

288,296,304

Step-by-step explanation:

let's take the 3 consecutive multiples as

x,x+8,x+16

sum=888

x+x+8+x+16=888

3x+24=888

3x=864

x= 288

Therefore,

consecutive multiples are

x,x+8,x+16

288, 288+8, 288+16

288,296,304