Question

The sum of three consecutive multiples of 8 is 888. Find the multiples​

Answer 1

hey mate good evening,

here is your answer.

let the first no. be = x

second no. be = x+8

third no. be = x+16

sum of these consecutive multiples are 888.

(x) + (x+8) + (x+16) = 888

3x + 24 = 888

3x = 888 - 24

3x = 864

x = 864/3

:. x = 288

:. the first no. = x = 288

second no. = x+8 = 296

third no. = x + 16 = 304.

CHECK :-

288 + 296 + 304 = 888

584 + 304 = 888

888 = 888

hope it helps....

Answer 2

Let the three consecutive multiples of 8 be 8x, 8(x+1) and 8(x+2).

According to the question,

8x + 8(x+1) + 8(x+2) = 888

⇒ 8 (x + x+1 + x+2) = 888 (Taking 8 as common)

⇒ 8 (3x + 3) = 888

⇒ 3x + 3 = 888/8

⇒ 3x + 3 = 111

⇒ 3x = 111 – 3

⇒ 3x = 108

⇒ x = 108/3

⇒ x = 36

Thus, the three consecutive multiples of 8 are:

8x = 8 × 36 = 288

8(x + 1) = 8 × (36 + 1) = 8 × 37 = 296

8(x + 2) = 8 × (36 + 2) = 8 × 38 = 304