Question

the sum of three consecutive multiples of 8 is 888 . find the multiples give full step

Answer 1

Let the first number be 8a

Second number = 8a +8

Third number = 8a +16

According to question

8a + 8a +8 + 8a + 16 = 888

=> 24a + 24 = 888

=> 24a = 864

=> a = 36

First number = 36 * 8 = 288

Second number = 296

Third number = 304

Answer 2

let the first consecutive multiple of 8 be x
second consecutive multiple be x+8
third consecutive multiple be x+8+8= x+16
A.T.Q
x+x+8+x+16=888
3x+24=888
3x=888-24
3x=864
x=864/3
x=288
first number =x=288
second number=x+8=288+8=296
third number =x+16=288+16=304