Question

The sum of three consecutive multiples of 8 is 888.Find the multiples.​

Answer 1

Answer:

Given that the sum of these multiples is 888. The multiples of 8 are: 8n - 8 = 296 - 8 = 288.

Step-by-step explanation:

Let 3 consecutive multiple of 8

8x,8(x+1),8(x+2)

Sum=8x+8(x+1)+8(x+2)=888

8(x+x+x+1+2)=888

3(x+1)=111

x+1=

3

111

x+1=37

x=36

First multiple =8x=8×36=288

Second =8(x+1)=8×37=296

Third =8(x+2)=8×38=304

Answer 2

Let the three consecutive multiples of 8 be 8x,

8(x+1) and 8(x+2).

According to the question

8x+8(x+1)+8(x+2)=888

8(x+x+1+x+2)=888(taking 8 as common)

8(3x+3)=888

3x+3=888/8

3x+3=111

3x=111-3

3x=108

x=108/3

x=36

Thus, the three consecutive multiples of 8 are:-

8x=8x36=288

8(x+1)=8x(36+1)=8x37=296

8(x+2)=8x(36+2)=8x38=304

Hope it helps