The sum of three consecutive multiples of 9 is 324 find those numbers
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Step-by-step explanation:
Assume three consecutive numbers : x,x+1,x+2.
The sum of three consecutive multiples of 9 is 324
9x+9(x+1)+9(x+2) = 324
9x+9x+9+9x+18 = 324
27x+27 = 324
27x = 297
x = 11
so numbers are 11,12,13
Smallest multiple = 9*11 = 99
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