The sum of three consecutive multiples of 9 is 378. find three multiples
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Answered by
7
let the three numbers be x, x+1,x+2.
9(x)+9(x+1)+9(x+2)=378
9x+9x+9+9x+18=378
27x=378-27=351
x=351/27=13
the three numbers are 13,14 and 15.
9(x)+9(x+1)+9(x+2)=378
9x+9x+9+9x+18=378
27x=378-27=351
x=351/27=13
the three numbers are 13,14 and 15.
Answered by
6
solution :-
Given:-
The sum of three consecutive multiples of 9 is 378.
Let the first number be x.
second number= x +9
Third number = x+9+9 = x+18
Now
x + x+ 9 + x+18 = 378
=>3x + 27 = 378
=>3x = 378 -27
=>x = 351/3
=>x = 117
first number = 117
second number = 117+9 = 126
third number = 117+18 = 135
so 117, 126 and 135 are the 3 consecutive multiples of 9 whose sum is 378.
Thanks
Given:-
The sum of three consecutive multiples of 9 is 378.
Let the first number be x.
second number= x +9
Third number = x+9+9 = x+18
Now
x + x+ 9 + x+18 = 378
=>3x + 27 = 378
=>3x = 378 -27
=>x = 351/3
=>x = 117
first number = 117
second number = 117+9 = 126
third number = 117+18 = 135
so 117, 126 and 135 are the 3 consecutive multiples of 9 whose sum is 378.
Thanks
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