Question

The sum of three consecutive multiples of 9 is 378. find three multiples

Answer 1

Let the multiples be 9(x-1), 9x, 9(x+1).

Given: 9(x-1)+9x+9(x+1)=378


So, 9x-9+9x+9x+9=378


So, 27x=378


=>x=14 

So, the multiples are 13 x 9, 14 x 9,15 x 9


=> They are 117, 126, 135.

Answer 2

solution :-

Given:-
The sum of three consecutive multiples of 9 is 378.

Let the first number be x.

second number= x +9

Third number = x+9+9 = x+18

Now

x + x+ 9 + x+18 = 378
=>3x + 27 = 378
=>3x = 378 -27
=>x = 351/3
=>x = 117

first number = 117

second number = 117+9 = 126

third number = 117+18 = 135

so 117, 126 and 135 are the 3 consecutive multiples of 9 whose sum is 378. 

Thanks