The sum of three consecutive multiples of 9 is 567. Find the largest of these nunber.
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5
Answer:
1. Let three consecutive multiple of 9 are x,x+1,x+2
2. then , (x+x+1+x+2)×9=567
3. x=20
4. 1st= 180,2nd = 189,3rd= 198
Answered by
1
Answer:
largest number is 198.
Step-by-step explanation:
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