Question

the sum of three consecutive multiples of 9 is 999.find these multiples

Answer 1

let the three number be x, x+9,x+18
therefore we can say
X + X + 9 + X + 18= 999
3x+27=999
x=324
3 number are 324, 333 and 342

Answer 2

solution :-

Given:-
The sum of three consecutive multiples of 9 is 378.

Let the first number be x.

second number= x +9

Third number = x+9+9 = x+18

Now

x + x+ 9 + x+18 = 999
=>3x + 27 = 999
=>3x = 999 -27
=>x = 972/3
=>x = 324

first number = 324

second number = 324+9 = 333

Third number = 324+18 = 342

Thanks