Question

the sum of three consecutive multiples of 9 is 999.find these multiples
Please do fast its urgent
Please help

Answer 1

$\textbf{Answer}$

Lets suppose the first multilple of 9 among those three consecutive multiples is xl(x-9)

=> Second consecutive multiple of 9 is x

=> Third consecutive multiple of 9 is (x+9).

Since according to the question,the sum of three consecutive multiple is 999.

=> (x-9) + x + (x+9) = 999

=> 3x = 999

=> x = 333

So the first multiple = x - 9 = 333 - 9 = 324

So the second consecutive multiple = x = 333

So the third consecutive multiple = x + 9 = 342

$\textbf{So the required multiples of 9 are 324,333,342}$

$\textbf{Hope It Helps}$

$\textbf{Thanks}$

Answer 2

solution :-

Given:-
The sum of three consecutive multiples of 9 is 378.

Let the first number be x.

second number= x +9

Third number = x+9+9 = x+18

Now

x + x+ 9 + x+18 = 999
=>3x + 27 = 999
=>3x = 999 -27
=>x = 972/3
=>x = 324

first number = 324

second number = 324+9 = 333

Third number = 324+18 = 342

Thanks