the sum of three consecutive multiples of 9 is 999. find these multiples.
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Given,
x, x + 9, x + 18 = 999
According to the question,
The three consecutive multiples at up to 999
3x + 27 = 999
3x = 999 - 27
3x = 972
x = 972/3
x = 324.
x+9 = 324+9 = 333
x+18 = 324+18 = 342.
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