Question

The sum of three consecutive multiples of five is 330.find the multiples?

Answer 1

Let the first no. be x
Then the second and third nos. will be x+5 and x+10 respectively
AC/Q
x+x+5+x+10=330
3x+15=330
3x=330-15
3x=315
x=315/3=105

The multiples are 105, 110 and 115.

Answer 2

Given:

Sum of 3 "consecutive multiples" of five is 330

To find:

The multiples of five.

Answer:

Given that the sum of 3 "consecutive multiples" of 5 are 330

Let assume the first number is X

Second number is X+5 and Third number is X+10

According to question  

X+X+5+X+10 = 330

3X+15 = 330

3X = 330-15

3X = 315

$= \frac {315}{3}$

X = 105

X+5 = 105+5 = 110

X+10 = 105+10 = 115

The First, Second and Third Consecutive numbers is 105, 110 and 115.