Question

The sum of three consecutive multiples os 8 is 888 find the multiple​

Answer 1

Answer:

Let 3 consecutive multiple of 8

8x,8(x+1),8(x+2)

Sum=8x+8(x+1)+8(x+2)=888

8(x+x+x+1+2)=888

3(x+1)=111

x+1=

3

111

x+1=37

x=36

First multiple =8x=8×36=288

Second =8(x+1)=8×37=296

Third =8(x+2)=8×38=304

Explanation:

Hope it will help

Answer 2

Solution

Let the three consecutive multiples of 8 be 8x, 8x + 8 and 8x + 16.

As per the conditions, we get

8x + (8x + 8) + (8x + 16) = 888

⇒ 8x + 8x + 8 + 8x + 16 = 888

⇒ 24x + 24 = 888

⇒ 24x = 888 – 24 (transposing 24 to RHS)

⇒ 24x = 864

⇒ x = 864 ÷ 24 (transposing 24 to RHS)

⇒ x = 36

Thus, the required multiples are

36 × 8 = 288,

36 × 8 + 8 = 296 and

36 × 8 + 16 = 304,

i.e., 288, 296 and 304.