the sum of three consecutive natural number is 36 . what are the numbers?
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- let 1st=x , 2nd=x+1 and 3rd= x+2,then , x+x+1+x+2=36 =3x+3=36, =3x=36-3 ,= 3x=33; =x=33/3=11; 1st=11 , 2nd=11+1=12 and 3rd= 11+2=13;hence ,11,12and13 is correct answer
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