The sum of three consecutive natural numbers each divisible by 3 is 72. what is the largest among them
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Answered by
8
Hi here is the answer.
Plz regard as brainliest.
Let the numbers be y,y+3,y+6.ok
So.y+y+3+y+6=72
3y+9=72
3y=72-9
y=63/3
y=21
Numbers are 21
21+3=24
21+6=28
Largest number 28....
Mark as brainliest pllzzz
Regards
Vatsalya
Plz regard as brainliest.
Let the numbers be y,y+3,y+6.ok
So.y+y+3+y+6=72
3y+9=72
3y=72-9
y=63/3
y=21
Numbers are 21
21+3=24
21+6=28
Largest number 28....
Mark as brainliest pllzzz
Regards
Vatsalya
Answered by
0
x+x+2+x+4=72
3x+6=72
3x=66
x=22
x+2=24
x+4=26
"Each divisible by 3 " makes no sense!
3x+6=72
3x=66
x=22
x+2=24
x+4=26
"Each divisible by 3 " makes no sense!
anwartabrez01:
Sorry send it to a wrong one
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