the sum of three consecutive natural numbers is 114. find the numbers
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6
a+d+a+a-d =114
3a=114
a=38
as it's consecutive than d=1
:. nos are 38,37.,39
3a=114
a=38
as it's consecutive than d=1
:. nos are 38,37.,39
Answered by
2
Let one number be x.
Then another no = x+1
Third no.=x+2
So x + (x+1) + (x+2) = 114
=>3x+3=114
=>3x=114-3
=>x=111/3
=>x=37
∴x=37
second no.=x+1=38
third no.=x+2=39
Then another no = x+1
Third no.=x+2
So x + (x+1) + (x+2) = 114
=>3x+3=114
=>3x=114-3
=>x=111/3
=>x=37
∴x=37
second no.=x+1=38
third no.=x+2=39
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