Question

the sum of three consecutive natural numbers is 114.find the numbers

Answer 1

Hi,

Here is your answer,

Let us consider the number be

x , x +1 , x + 2

So, According to the question,

x  +  x + 1 + x + 2= 114            { Given }

→ 3x + 3 = 114

→ 3( x + 1 ) = 114

→ x + 1 = 38

↔ x = 37 

Numbers are:- 

37 , 38 , 39 ∴ Required answer.


Hope it helps you !

Answer 2

☆ Given:-

• The sum of three consecutive natural numbers = 114

☆ To Find :-

• The numbers

☆ Let :-

• The first number = x

• The second number = x +

• The third number = x + 2

According to the question :-

$\sf \mapsto x +x + 1 + x + 2 =114$

$\sf \mapsto 3x + 3 = 114$

$\sf \mapsto 3x = 114-3$

$\sf \mapsto3x = 111$

$\sf \mapsto x = \large \frac{ \cancel{111}}{ \cancel3}$

$\sf \mapsto x = 37$

The value of x = 37

Therefore ,

• The first number = x = 37

• The second number = x + 1 = 37+1 = 38

• The third number = x+2 = 37+2 = 39