Question

the sum of three consecutive no is 276. find the number

Answer 1

Let the smallest of the 3 consecutive numbers be x.
Then the other two numbers are x+1 and x+2
Given the sum of theses numbers is 276
                                          x + x+1 + x+2 = 276
                                               3x + 3 = 276 
                                               3x = 276 - 3
                                               3x = 273
                                               x = 273/3
                                               x = 91.
∴ The required consecutive numbers are 91, 92 and 93.

Hope my answer helps you..

Answer 2

Here is your solution

Given :-

The sum of three consecutive numbers is 276.

Let consecutive number be x ,x+1,x+2

A/q

=>x+(x+1)+(x+2)=276
=>3x+3=276
=>3x=276-3
=>3x =273
=>x=91

The three consecutive numbers is

x = 91✔

x +1 = 91+1 =92 ✔

x+2 = 91+2 =93✔

The three consecutive numbers is 91,92,93

Hope it helps you