Question

the sum of three consecutive number is 114 finhd the numbers

Answer 1

Let the first number of consecutive numbers be α
∴ α+α+1+α+2=114
∴ 3α+3=114
∴ 3α=114-3
∴ α=$\frac{111}{3}$
∴ α=37 
∴ α+1=38
∴ α+2=39
∴ The consecutive numbers are 37, 38 and 39.