the sum of three consecutive number is 156.find the numbers which is a multiple of 13 out of these numbers.
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Answered by
3
Let the numbers be ( x - 1 ) , ( x ) , ( x + 1 )
Given that, x - 1 + x + x + 1 = 156
3x = 156
x = 156 / 3
x = 52
Therefore the other numbers are : ( x - 1 ) = 52 - 1 = 51 ; ( x + 1 ) = 52 + 1 = 53
All the three numbers are 51, 52, 53, out of which 52 is a multiple of 13.
Answered by
6
Here is your solution
Given :-
The sum of three consecutive numbers is 156
Let consecutive number be x ,x+1,x+2
A/q
=>x+(x+1)+(x+2)= 156
=>3x+3=156
=>3x=156-3
=>3x = 153
=>x=51
The three consecutive numbers is
x = 51
x +1 = 51+1 = 52
x+2 = 51+2 = 53
The three consecutive numbers is 51,52,53
Hence
52 is multiple of 13✔
Hope it helps you
Given :-
The sum of three consecutive numbers is 156
Let consecutive number be x ,x+1,x+2
A/q
=>x+(x+1)+(x+2)= 156
=>3x+3=156
=>3x=156-3
=>3x = 153
=>x=51
The three consecutive numbers is
x = 51
x +1 = 51+1 = 52
x+2 = 51+2 = 53
The three consecutive numbers is 51,52,53
Hence
52 is multiple of 13✔
Hope it helps you
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