Question

the sum of three consecutive numbers divisible by 3 is 108. find these numbers
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Answer 1

Answer:

three consecutive numbers are x , x+1 and x+2

ATQ

x+3 x+6 + x+9 = 108

3x + 18= 108

3x = 108 - 18

x = 90

x + 3= 90+ 3= 93

x + 6 = 90 + 6 = 96

x+9 = 90 + 9 = 99

... may this help you

Answer 2

let the number divisible by 3 be x

three consecutives numbers will be x +3 and x + 6

ATQ,

• x + x + 3 + x + 6 = 108
• 3x = 108 - 9
• x = 33

1. x = 33
2. 33 + 3 = 36
3. 33 + 6 = 39...

Thnx...