Question

the sum of three consecutive numbers divisible by3 is 108 find these numbers

Answer 1

I think consecutive shouldn't come
therefore,
3x+3x+3+3x+6 =108
9x+9=108
9x=99
x=11
3x = 11×3=33
3x+3=3×11+3=36
3x+6=3×11+6=39

Answer 2

$\huge\bf{Answer:-}$

180 is the sum

x + x + 1 + x + 2 = 108

3x + 3 = 108

3x = 108 - 3

3x = 105

x = 105/3

= 35

Hence, 35 is the value of x